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8x^2=660
We move all terms to the left:
8x^2-(660)=0
a = 8; b = 0; c = -660;
Δ = b2-4ac
Δ = 02-4·8·(-660)
Δ = 21120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{21120}=\sqrt{64*330}=\sqrt{64}*\sqrt{330}=8\sqrt{330}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{330}}{2*8}=\frac{0-8\sqrt{330}}{16} =-\frac{8\sqrt{330}}{16} =-\frac{\sqrt{330}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{330}}{2*8}=\frac{0+8\sqrt{330}}{16} =\frac{8\sqrt{330}}{16} =\frac{\sqrt{330}}{2} $
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